实验十 二叉树的基本操作
| May 27, 2008 16:34 | timmy | Via Original
Test10.cpp
#include<iostream.h>
#include<stdlib.h>
#include<stdio.h>
typedef char ElemType;
struct BTreeNode{
ElemType data;
BTreeNode* left;
BTreeNode* right;
};
#include "test9_stack.h"
#include "test10.h"
void main()
{
BTreeNode* bt;
InitBTree(bt);
char b[50];
cout<<"输入二叉树用广义表表示的字符串:"<<endl;
cin.getline(b,sizeof(b));
CreateBTree(bt,b);
PrintBTree(bt);
cout<<endl;
cout<<"前序:";
PreOrder(bt);
cout<<endl;
cout<<"中序:";
InOrder(bt);
cout<<endl;
cout<<"中序(非递归算法):";
InOrder_fdg(bt);
cout<<endl;
cout<<"后序:";
PostOrder(bt);
cout<<endl;
cout<<"按层:";
LevelOrder(bt);
cout<<endl;
ElemType x;
cout<<"输入一个待查字符:"<<endl;
cin>>x;
if(FindBTree(bt,x))
cout<<"查找字符"<<x<<"成功!"<<endl;
else
cout<<"查找字符"<<x<<"失败!"<<endl;
cout<<"深度:";
cout<<DepthBTree(bt)<<endl;
if(ChangeBTree(bt)){
printf("将二叉树中的所有结点的左右子树进行交换后: \n");
PrintBTree(bt);
cout<<endl;
}
printf("二叉树中的结点总数: %d \n",CountBTree(bt));
BTreeNode* newbt;
newbt=CopyBTree(bt);
printf("复制二叉树得新二叉树:\n");
PrintBTree(newbt);
ClearBTree(bt);
ClearBTree(newbt);
}
#include<iostream.h>
#include<stdlib.h>
#include<stdio.h>
typedef char ElemType;
struct BTreeNode{
ElemType data;
BTreeNode* left;
BTreeNode* right;
};
#include "test9_stack.h"
#include "test10.h"
void main()
{
BTreeNode* bt;
InitBTree(bt);
char b[50];
cout<<"输入二叉树用广义表表示的字符串:"<<endl;
cin.getline(b,sizeof(b));
CreateBTree(bt,b);
PrintBTree(bt);
cout<<endl;
cout<<"前序:";
PreOrder(bt);
cout<<endl;
cout<<"中序:";
InOrder(bt);
cout<<endl;
cout<<"中序(非递归算法):";
InOrder_fdg(bt);
cout<<endl;
cout<<"后序:";
PostOrder(bt);
cout<<endl;
cout<<"按层:";
LevelOrder(bt);
cout<<endl;
ElemType x;
cout<<"输入一个待查字符:"<<endl;
cin>>x;
if(FindBTree(bt,x))
cout<<"查找字符"<<x<<"成功!"<<endl;
else
cout<<"查找字符"<<x<<"失败!"<<endl;
cout<<"深度:";
cout<<DepthBTree(bt)<<endl;
if(ChangeBTree(bt)){
printf("将二叉树中的所有结点的左右子树进行交换后: \n");
PrintBTree(bt);
cout<<endl;
}
printf("二叉树中的结点总数: %d \n",CountBTree(bt));
BTreeNode* newbt;
newbt=CopyBTree(bt);
printf("复制二叉树得新二叉树:\n");
PrintBTree(newbt);
ClearBTree(bt);
ClearBTree(newbt);
}











